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Submitted: November 09, 2023 | Approved: December 07, 2023 | Published: December 08, 2023

How to cite this article: Patil J, Hardan B, Hamoud AA, Ghadle KP, Abdallah AA. Adjusted Hardy-Rogers-Type Result Generalization. Int J Phys Res Appl. 2023; 6: 199-202.

DOI: 10.29328/journal.ijpra.1001073

Copyright License: © 2023 Patil J, et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited.

Keywords: Fixed point; Contractive type; Existence/Uniquensess

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Adjusted Hardy-Rogers-Type Result Generalization

Jayashree Patil1, Basel Hardan2*, Ahmed A Hamoud3, Kirtiwant P Ghadle4 and Alaa A Abdallah5

1Department of Mathematics, Vasantrao Naik Mahavidyalaya, Cidco, Chhatarapati Sambhaji Nagar, India
2,4,5Department of Mathematics, Dr. Babasaheb Ambedkar Marathwada University, Chhatarapati Sambhaji Nagar 431004, India
3Department of Mathematics, Taiz University, Taiz P.O. Box 6803, Yemen
2,5Department of Mathematics, Abyan University, Abyan 80425, Yemen

*Address for Correspondence: Basel Hardan, Department of Mathematics, Dr. Babasaheb Ambedkar Marathwada University, Chhatarapati Sambhaji Nagar 431004, India, Email: bassil2003@gmail.com

The adjusted Hardy-Rogers result generalization for the fixed point is demonstrated in this study, validating our results utilizing an application.

The existence and uniqueness of a point ξ ∈ X, such that T: X → X, is a contraction mapping where X is a complete metric space was proved by Banach [1].

d(fξ,fζ)αd(ξ,ζ), (1)

for all ξ, ζ ∈ X and α [0,1). Kannan [2] developed (1) as

d(fξ,fζ)α[d(fξ,ξ)+d(fζ,ζ)], (2)

for all ξ, ζ ∈ X and α(0, 1 2 ) . Reich in [3] generalized (2) as

d(fξ,fζ)[ η 1 d(ξ,ζ)+ η 2 d(fξ,ξ)+ η 3 d(fζ,ζ)], (3)

for all ξ, ζ ∈ X such that η1 + η2 + η3 < 1. Then f has a unique fixed point in X.

In the same direction, Hardy and Rogers in [4] introduced the following

Theorem 1.1

Let (X, d) be a metric space and f a self mapping of X satisfies

d(fξ,fζ) η 1 d(ξ,fξ)+ η 2 d(ζ,fζ)+ η 3 d(ξ,fζ)+ η 4 d(ζ,fξ)+ η 5 d(ξ,ζ), (4)

for ξ, ζ ∈ X where η1, η2, η3, η4, η5 are non-negative and we set α = η1 + η2 + η3 + η4 + η5. Then,

If X is complete metric space and α1, f has a unique fixed point.

If (4) is adjusted to the condition ξ ≠ ζ implies

d(fξ,fζ) η 1 d(ξ,fξ)+ η 2 d(ζ,fζ)+ η 3 d(ξ,fζ)+ η 4 d(ζ,fξ)+ η 5 d(ξ,ζ). (5)

Such that X is a compact with continuous mapping and α + 1, then f has a unique fixed point.

Recently, many of the Hardy-Rogers-type notions have been developed. From these studies, we refer to Rangama [5] established the existence of the Hardy-Rogers-type common fixed point in 2-metric space. With respect to the aiding function, Chifu [6] provided a few fixed point theorems in b-metric space utilizing the Hardy-Rogers type. New Hardy-Rogers-type results have been provided by Patil, et al. [7]. Victoria [8] obtained the P-proximate cyclic contraction in the uniform spaces utilizing the Hardy-Rogers type. Using partially ordered partial metric space, Abbas [9] developed a few fixed point theorems for the Hardy-Rogers type. The common fixed point theorem for T-Hardy-Rogers contraction mapping in a cone metric space was established by Rhymend, et al. in [10]. Saipara generalized some fixed point theorems for Hardy-Rogers-type in metric-like space [11]. Raghavendran, et al. [12] included a recent article relevant to the focused topic.

We will introduce and prove the adjusting generalization of the Hardy-Rogers type as

Theorem 2.1

Let {fa} be a family continuous self-mappings in a complete metric space X, suppose that

+ η 5 d(ξ,ζ) (6)

for every ξ, ζ ∈ X, ξ ≠ ζ and η 1 , η 2 , η 3 , η 4 , η 5 i=1 5 η i 1. Then fα (ξ) has a unique fixed point u1 ∈ X.

Proof. For ξ 0 , ζ 0 X take f α ( ξ n1 )= ξ n , g β ( ζ n1 )= ζ n ,

d( x k , y k )=d( f α ( ξ k1 , g β ( ζ k1 ))

η 1 d( ξ k1 , f α ( ξ k1 ))+ η 2 d( ζ k1 ,g( ζ k1 )+ η 3 d( ξ k1 ,g( ζ k1 )

+ η 4 d( ζ k1 , f α ( ξ k1 + η 5 d( ξ k1 , ζ k1 )),k. (7)

So,

k=1 n d( x k , y k )= k=1 n d( f α 1 ( ξ k1 , f α 2 ( ζ k1 ))

k=1 n [ η 1 d( ξ k1 , ξ k )+ η 2 d( ζ k1 , ζ k )+ η 3 d( ξ k1 , ζ k )+ η 4 d( ζ k1 , ξ k )

+ η 5 d( ξ k1 , ζ k1 )]

[ η 1 d( ξ 0 , ξ n )+ η 2 d( ζ 0 , ζ n )+ η 3 k=1 n d( ξ k1 , ζ k )+ k=1 n η 4 d( ζ k1 , ξ k )

+ k=1 n η 5 d( ξ k1 , ζ k1 )].

Also,

k=1 n d( ξ k+1 , y k )[ η 1 d( ξ 1 , ξ n )+ η 2 d( ζ 0 , ζ n )+ η 3 k=1 n d( ξ k , ζ k )+ k=1 n η 4 d( ζ k1 , ξ k )

+ k=1 n η 5 d( ξ k1 , ζ k1 )],

and,

k=1 n d( ξ k , ξ k+1 )( η 1 + η 5 )d( ξ 0 , ξ n )+( η 2 + η 3 )d( ξ 1 , ξ n+1 ).

Then,

k=1 n d( ξ k , ξ k+1 ) k=1 n d( ξ k , y k ) k=1 n d( ξ k+1 , y k ). (8)

Therefore, k=1 n d( ξ k , ξ k+1 )0ask , hence {XK} is a Cauchy sequence. Also, {YK} is a Cauchy sequence in X, and since X is a complete metric space, there exists a common fixed point in X.

Suppose that,

u 1 = lim n ξ n , u 2 = lim n ζ n , u 1 , u 2 X,

we get,

d( ξ n , u 1 )0,n,

d( ζ n , u 1 )0,n.

since, fα, gβ are continuous mappings we obtained,

d( f α ( ξ n ), f α ( u 1 ))0,n,

d( g β ( ζ n ), g β ( u 2 ))0,n.

We have

d( u 1 , f α ( u 1 ))=d( f α 1 ( f α ( u 1 )), f α ( u 1 ))

η 1 d( f α 1 ( f α ( u 1 )), f α ( u 1 ))+ η 2 d( u 1 , f α ( u 1 ))+ η 3 d( f α ( u 1 ), f α ( u 1 ))

+ η 4 d( u 1 , f α 1 ( f α ( u 1 )))+ η 5 d( f α ( u 1 ), u 1 )

=( η 1 + η 2 + η 5 )d( u 1 , f α ( u 1 )).

Hence, f α ( u 1 )= u 1 .

likewise, we can prove that gβ (u2) = u2. Now, we will prove that u1 is a common fixed point of fα and , as

d( u 1 , u 2 ) η 1 d( u 1 , f α 1 ( u 1 ))+ η 2 d( u 2 , f α 2 ( u 2 ))+ η 3 d( u 1 , f α 2 ( u 2 ))+ η 4 d( u 2 , f α 1 ( u 1 ))

+ η 5 d( u 1 , u 2 )

=( η 3 + η 4 + η 5 )d( u 1 , u 2 ).

Consider u3 ∈ X such that it can be used to demonstrate the uniqueness of u1.

f α ( u 3 )= u 3 ,and g β ( u 3 )= u 3 .

Therefore

d( u 1 , u 3 )=( f α 1 ( u 1 ), f α 3 ( u 3 ))

η 1 d( u 1 , f α 1 ( u 1 ))+ η 2 d( u 3 , f α 2 ( u 3 ))+ η 3 d( u 1 , f α 2 ( u 3 ))

+ η 4 d( u 3 , f α 1 ( u 1 ))+ η 5 d( u 1 , u 3 )

=( η 3 + η 4 + η 5 )d( u 1 , u 3 ).

Hence,

u 1 = u 2 = u 3 .

Thus, u1 is the unique fixed point of fα and .

Theorem 2.1 can be stated as follows:

Theorem 2.2

Let fk be a self-mappings on X, such that f k ( z k )= z k ,ξXand z k Xk respectively, such that

d( f k (ξ), f k (ζ)) η 1 d(ξ, f k (ξ))+ η 2 d(ζ, f k (ζ))+ η 3 d(ξ, f k (ζ))+ η 4 d(ζ, f k (ξ))+ η 5 d(ξ,ζ). (9)

For all ξ, ζ ∈ X, ξ ≠ ζ and i=1 5 η i 1.

Proof. Theorem 2.1 may be proven using the same way used to prove Theorem 2.2.

Our main result has corollaries, we leave their proof for the reader.

Corollary 2.3

Let X be a complete metric space and let f : X → \mathbb{R} a continuous self-mapping on X, let f satisfying (4) for all ξ, ζ ∈ X, ξ ≠ ζ and for some η1, η2, η3, η4, η5 ∈ [0,1) such that

i=1 5 η i . Then f has a unique fixed point.

Corollary 2.4

Let X be a complete metric space and let f, g are two continuous self-mappings on X satisfying

d(f(ξ),g(ζ)) η 1 d(ξ,f(ξ))+ η 2 d(ζ,g(ζ))+ η 3 d(ξ,g(ζ))+ η 4 d(ζ,f(ξ))+ η 5 d(ξ,ζ) (10)

for all ξ, ζ ∈ X, ξ ≠ ζ and for some η1, η2, η3, η4, η5 ∈ [0,1) such that i=1 5 η i 1. Then f and g have a unique fixed point.

The existence and uniqueness of a common fixed point of two mappings that are not necessarily continuous can be investigated using our findings by introducing the next theorem [13-15].

Theorem 2.5

Let fα1, fα2 be two self-mappings on a complete metric space X, satisfies

for all ξ, ζ ∈ X, ξ ≠ ζ and i=1 5 η i 1. Suppose that 1,fα2 = fα21 is continuous then 1 and fα2 having a unique common fixed point in ξ.

Proof. Take ξ n =f α 1 ( ξ n1 ), ξ n =f α 2 ( ξ n1 )andf α 1 ( ξ n1 )f α 2 ( ξ n1 ), ξ n ξ n1 ,n. Therefore,

d( ξ 2n+1 , ξ 2n )=d(f α 1 ( ξ 2n ),f α 2 ( ξ 2n1 ))

η 1 ( ξ 2n ,f α 1 ( ξ 2n ))+ η 2 ( ξ 2n1 ,f α 2 ( ξ 2n1 ))+ η 3 ( ξ 2n ,f α 2 (( ξ 2n1 ))

+ η 4 (( ξ 2n1 ,f α 1 ( ξ 2n ))+ η 5 ( ξ 2n , ξ 2n1 )

= η 1 ( ξ 2n , ξ 2n+1 )+ η 2 ( ξ 2n1 , ξ 2n )+ η 3 ( ξ 2n , ξ 2n )+ η 4 ( ξ 2n1 , ξ 2n+1 )

+ η 5 ( ξ 2n , ξ 2n1 ).

So, we have

d( ξ 2n+1 , ξ 2n )( η 2 + η 4 + η 5 1 η 2 η 4 )d( ξ 2n , ξ 2n1 ). (11)

From (11) we obtain

d( ξ 2n+1 , ξ 2n ) ( η 2 + η 4 + η 5 1 η 2 η 4 ) 2n d( ξ 1 , ξ 0 ). (12)

We get

f α 1 f α 2 ( u 1 )=f α 2 f α 1 ( u 1 )=f α 1 f α 2 ( lim k ξ n k )= lim k ξ n k+1 = u 1 .

Let u1 is a fixed point of f12 such that fα12 (u1)= u1. Now, we must show that fα1 (u1)= u1 and fα2 (u1)= u1. For that we let fα1 (u1) ≠ u1 and fα2 (u1) ≠ u1. Then,

d( u 1 ,f α 1 ( u 1 ))=d(f α 2 f α 1 ( u 1 ),f α 1 ( u 1 ))

η 1 d(f α 1 ( u 1 ),f α 2 f α 1 ( u 1 )+ η 2 d( u 1 ,f α 1 ( u 1 ))+ η 3 d(f α 1 ( u 1 , f 1 ( u 1 )

+ η 4 d( u 1 ,f α 1 (f α 1 ( u 1 )))+ η 5 d(f α 1 ( u 1 ), u 1 )=0.

Hence,

u1 is a fixed point of 1. Similarly we can get 2 (u1)= u1. This indicates that 1 and fα2 have a common fixed point in X. That was proof of existence.

As for proving uniqueness, let's suppose u2 ∈ X, u2 ≠ u1 be another fixed point of f1 and fα2. Then

d( u 1 , u 2 )=d(f α 1 ( u 1 ),f α 2 ( u 2 ))

η 1 d( u 1 ,f α 1 ( u 1 ))+ η 2 d( u 2 ,f α 2 ( u 2 ))+ η 3 d( u 1 ,f α 2 ( u 2 )+

η 4 d( u 2 ,f α 1 ( u 1 )+ η 5 d( u 1 , u 2 )=( η 3 + η 4 + η 5 )d( u 1 , u 2 )=0.

We have demonstrated a uniqueness and completed proof of the theorem.

  1. Banach S. On Operations in Abstract Sets and Their Application to Equations, Integrals Fundam. Math. 1922; 3:133-181.
  2. Kannan R. Some remarks on fixed points, Bull Calcutta Math. Soc. 1968; 60:71-76.
  3. Reich S. Kannan's fixed point theorem, Bull, Univ. Mat. Italiana. 1971; (4) 4:1-11.
  4. Hardy GE, Rogers TD. A generalization of fixed point theorem of Reich, Canada. Math. Bull. 1973; 16(2):201-206.
  5. Rangamma M, Bhadra P. Hardy and Rogers type contractive condition and common fixed point theorem in cone-2-metric space for a family of self-maps, Global journal of pure and applied mathematics. 2016; 12(3):2375-2385.
  6. Chifu C, Patrusel G. Fixed point results for multi valued Hardy-Rogers contractions in b-metric spaces. Faculty of sciences and mathematics. University of Nic, Serbia. 2017;31(8):2499-2507.
  7. Patil J, Hardan B, Ahire Y, Hamoud A, Bachhav A. Recent advances on fixed point theorems, Bulletin of Pure & Applied Sciences- Mathematics and Statistics. 2022; 41(1):34-45.
  8. Olisama V, Olalern J, Akewe H. Best proximity point results for Hardy-Rogers p-proximal cyclic contraction in uniform spaces, fixed point theory and applications. 2018; 18:15 pages.
  9. Abbas M, Aydi H, Radenović S. Fixed point of T-Hardy-Rogers contractive mappings in partially ordered partial metric spaces. International journal of mathematics and mathematical sciences. 2012(2022); 11 pages.
  10. Rhymend V, Hemavathyy R. Common fixed point theorem for T-Hardy-Rogers contraction mapping in a cone metric space, International mathematical forum. 2010; 30(5):1495-1506.
  11. Saipara P, Khammahawong K. Fixed point theorem for a generalized almost Hardy-Rogers- type F-cotractive on metric-like spaces, Mathematical methods in the applied sciences. 2019; 42(39):5898-5919.
  12. Raghavendran P, Gunasekar T, Balasundaram H, Santra SS, Majumder D, Baleanu D. Solving fractional integro-differential equations by Aboodh transform. J. Math. Computer Sci. 2023; 32:229-240.
  13. Hardan B, Patil J, Hamoud AA, Bachhav A. Common fixed point theorem for Hardy-Rogers contractive type in Cone 2-metric spaces and its results, Discontinuity, Nonlinearity, and Complexity. 2023; 12(1):197-206
  14. Hamoud A, Patil J, Hardan B, Bachhav A. Coincidence point and common fixed point theorem for generalized Hardy-Rogers type -contraction mappings in a metric like space with an application, Dynamic of continuous, Discrete and Implsive System Series B: Applications and Algorithms. 2021; 27:268-281.
  15. Patil J, Hardan B, Hamoud A, Bachhav A, Emadifar H, Gnerhan H. Generalization contractive mappings on rectangular b-metric space, Advances in Mathematical Physics. 2022; 2022: Article ID 7291001.